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Non-uniform line charge density with r not constant

  1. Sep 27, 2007 #1
    1. The problem statement, all variables and given/known data

    We have a non uniform line charge density [tex]P_{l}[/tex] = [tex]\rho_{l}[/tex] cos[tex]\phi[/tex]

    It is a spiral line where 0 [tex]\leq[/tex] [tex]\phi[/tex] [tex]\leq[/tex] 4 [tex]\pi[/tex]

    It is on the x-y plane with z=0.

    r varies: r ( [tex]\phi[/tex] ) = [tex]\phi[/tex] * [tex]r_{0}[/tex] + a

    We need to find the Potential and Electric Field at the origin.

    2. Relevant equations

    V = (KQ/r)

    E = (KQ)/ r[tex]^{2}[/tex]

    E = -[tex]\nabla[/tex]V

    3. The attempt at a solution

    The east way would be to find the Potential and then to find the Electric Field by using the relationship between E and the gradient of V.

    I think this problem wouldn't be as tough if r was constant.
    Last edited: Sep 27, 2007
  2. jcsd
  3. Sep 27, 2007 #2
    So are you going to use a line integral? I suggest cylindrical coordinates.

    Also, I don't know what phi is, the polar angle or some constant? Oh, nevermind I see where r is bounded. You still need to show some work before you get any help.
    Last edited: Sep 27, 2007
  4. Sep 27, 2007 #3
    I've tried it, and I have gotten to the point where I have an integral that determines the potential at this point. Here's how I got this far:

    For a bunch of separate point charges, we have

    [tex]V = \sum {\frac {-1}{4 \pi \epsilon_{o} } \frac {q_i}{r_i} }[/tex]
    where I've replaced [tex]\rho_l[/tex] with [tex]\lambda[/tex] to make things easier for me. (Sometimes [tex]\rho[/tex] denotes the radial distance.)

    For a line, we replace [tex]q[/tex] with [tex]d \lambda[/tex] and integrate. To do this, we need to replace [tex]d \lambda[/tex] with something with [tex]d \phi[/tex] in it; I'll leave the details up to you. We replace [tex]r[/tex] with your formula for [tex]r[/tex].
  5. Sep 27, 2007 #4
    Can I fix your formulas too?

    [tex] V = k \int_{\Omega} \frac{\rho(\mathbf{r'})}{||\mathbf{r} - \mathbf{r'}||} d\gamma'[/tex]

    Which would specifically be

    [tex] V = k \int_l \frac{\lambda(\mathbf{r'})}{||\mathbf{r} - \mathbf{r'}||} dl'[/tex]

    for a line charge.
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