Nonlinear Differential Equation Homework Attempt

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SUMMARY

The discussion revolves around solving the nonlinear differential equation r" = 1/r^2. Participants agree that the equation is nonlinear and explore methods to approach it, specifically through integration. A key technique mentioned is multiplying both sides by r', which leads to the first integral. This method simplifies the problem, allowing for easier integration of the resulting expressions.

PREREQUISITES
  • Understanding of nonlinear differential equations
  • Familiarity with integration techniques
  • Knowledge of derivatives and their properties
  • Basic calculus concepts, including the chain rule
NEXT STEPS
  • Study the method of integrating nonlinear differential equations
  • Learn about the relationship between derivatives and integrals in calculus
  • Explore techniques for solving second-order differential equations
  • Investigate the application of conservation laws in differential equations
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Students and educators in mathematics, particularly those focusing on differential equations, as well as anyone interested in advanced calculus techniques.

Fizz_Geek
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Homework Statement



r" = 1/r^2

Homework Equations



A friend gave this to me, he was just wondering how we'd approach it.

The Attempt at a Solution



I don't think the equation is linear, so I don't know how to approach it. My friend suggested integrating both sides with respect to r, but we don't know if that's legal because we don't know what r might be a function of.
 
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Multiple both sides by r' and that will give you the first integral.
 
hunt_mat said:
Multiple both sides by r' and that will give you the first integral.

How's does multiplying by a derivative give me an integral?
 
As
<br /> r&#039;&#039;=\frac{1}{r^{2}}<br />
Multiply both sides by r' to obtain:
<br /> r&#039;r&#039;&#039;=\frac{r&#039;}{r^{2}}\Rightarrow\left(\frac{(r&#039;)^{2}}{2}\right) &#039;=\left( -\frac{1}{r}\right) &#039;<br />
Integrate easily from here.
 
Did you try it? What is the derivative of (r&#039;)^2? So what is the integral of r&#039; r&#039;&#039;? What is the integral of dr/r^2?
 
To hunt_mat:

That's a very nice trick! I got stuck on the next step, integrating (r')2, but I'll try to work that out with my friend before asking again.

Thanks very much!
 
It's a standard trick, become familier with it.
 

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