# Nonlinear differential equation

## Homework Statement

In one problem I had got to this equations, but I was not able to solve it, because I'm actually
on high school.

The equation :
d^2/dt^2(x) = -h*g/(h+x)

I tried use separation of variables but I was not able to use the chain rule.
Can anybody show me the steps with explanation?

Last edited by a moderator:

Related Calculus and Beyond Homework Help News on Phys.org
tiny-tim
Homework Helper
welcome to pf!

hi mbadin! welcome to pf! (try using the X2 button just above the Reply box )
d2x/dt2 = -h*g/(h+x)
either multiply both sides by dx/dt

or use d2x/dt2 = vdv/dx

(where v = dx/dt … you can prove it using the chain rule )

DryRun
Gold Member
OK, here is how your equation appears to me:
$$\frac{d^2x}{dt^2} = -\frac{hg}{h+x}$$
If i understood your question correctly, then you need to integrate twice to get rid of the differentiation.

HallsofIvy
Homework Helper
OK, here is how your equation appears to me:
$$\frac{d^2x}{dt^2} = -\frac{hg}{h+x}$$
If i understood your question correctly, then you need to integrate twice to get rid of the differentiation.
It's not that easy because the right side, that you want to integrate with respect to t depends upon the unknown function x.

I would do what tiny-tim suggested: Let v= dx/dt so that $d^2x/dt^2= dv/dt$ and then, by the chain rule,
$$\frac{dv}{dt}= \frac{dv}{dx}\frac{dx}{dt}= v\frac{dv}{dx}$$

$$v\frac{dv}{dx}= -\frac{hg}{h+ x}$$
$$\int v dv= hg\int \frac{dx}{h+ x}$$