A non-uniformly charged semicircle of radius R=18.5 cm lies in the xy plane, centered at the origin, as shown. The charge density varies as the angle θ (in radians) according to λ = − 4.42 θ, where λ has units of μC/m.What is the total charge on the semicircle?(adsbygoogle = window.adsbygoogle || []).push({});

2. Relevant equations: Q=(lambda)/L, L=(theta)*radius

I calculate Q to be (lambda)*L, or Q=(-4.42*(theta))*(.185*(theta)). I then ran this over the integral from theta=zero to theta=(pi). I got an answer in micro-Coulombs so I converted it to Coulombs to answer. I ended up with -8.4513E10^-6, but it says that It's incorrect...help!?!?! due at 11 tonight!

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# Homework Help: Nonuniformly charged semicircle

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