Norm of Laplacian Let: Formula for | ∇X|² in Coordinates

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SUMMARY

The discussion focuses on deriving the formula for the norm of the covariant derivative of a vector field, specifically |∇X|², in the context of a manifold (M,g) with a Levi-Civita connection ∇. The participants clarify that |X|² is expressed as g(X,X) and that the covariant derivative ∇X is represented as ∇_i X^j = ∂_i X^j + Γ^j_{il} X^l. The confusion arises around the correct interpretation of |∇X|², with the suggestion that it may be computed as (∇_i X^j)(∇_j X^i), highlighting the need for a clear definition of the norm for the (1,1) tensor.

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  • Understanding of differential geometry concepts, particularly manifolds and Levi-Civita connections.
  • Familiarity with tensor notation and operations, including covariant derivatives.
  • Knowledge of the metric tensor and its role in defining norms, specifically g(X,X).
  • Basic proficiency in calculus, particularly partial derivatives and their applications in vector fields.
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  • Study the properties of Levi-Civita connections in differential geometry.
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  • Investigate the relationship between the metric tensor and covariant derivatives in the context of curvature.
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user2010
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Let ##(M,g)## a manifold with a Levi-Civita connection ## \nabla ## and ##X## is a vector field.
What is the formula of ## | \nabla X|^2 ## in coordinates-form?

I know that ##|X|^2= g(X,X)## is equivalent to ## X^2= g_{ij} X^iX^j## and ##\nabla X## to ##\nabla_i X^j = \partial_i X^j + \Gamma^j_{il} X^k ## but I can't use these to ## | \nabla X|^2 ##.
 
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What do you mean by ##|\nabla X|^2##? The object ##\nabla X## is a type (1,1) tensor and if you want to compute its norm you need to define it.
 
I am confused with the norms and the covariant derivatives. I know that ##||A||^2 = A_{ij} A^{ij}= g_{ik} g_{jl} A^{kl} A^{ij}## for a (0-2) tensor.

So if ##\nabla X## is ##\nabla_i X^j = \partial_i X^j + \Gamma^j_{il} X^l ##, is

## | \nabla X|^2 ## equal to ## (\nabla_i X^j) (\nabla_j X^i) ## ?
 

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