Normal force between ball and cone?

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SUMMARY

The discussion centers on calculating the normal force (FN) between a ball and a cone using the equations of motion. The user initially miscalculated FN by neglecting to include the mass of the ball in their calculations. After realizing the need to consider the components of the forces involved, they successfully solved the problem, which involved applying the equations of motion, specifically ∑FX = FN and ∑Fy = -mg. The user also mentioned transitioning to impulse and momentum concepts following the resolution of their initial query.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with force components in physics
  • Knowledge of circular motion equations
  • Basic principles of impulse and momentum
NEXT STEPS
  • Study the derivation of normal force in inclined planes
  • Learn about the application of Newton's second law in circular motion
  • Explore the concept of impulse and momentum in collision scenarios
  • Investigate the relationship between mass, velocity, and force in dynamic systems
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators looking for examples of force calculations in circular motion scenarios.

isukatphysics69
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Homework Statement


CONE.PNG


Homework Equations



f=ma
v^2/r

The Attempt at a Solution


∑FX= FN
∑Fy= -mg
We are not given an angle, i would have put FNcos(θ).
I have my radius as 0.25 by relation of the triangles at that point of the height being .50m
so ∑FX= FN = v^2/r = (1.2)^2/.25 = 6.25N
 

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I forgot the mass...
 
Ok nevermind i just forgot to multiply by the mass converted to kilograms
 
wat.PNG

does anyone know why i am only getting partial credit?
 

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isukatphysics69 said:
∑FX= FN
FN is not horizontal.
 
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haruspex said:
FN is not horizontal.
Hi yes i marked this one solved guys i figured it out i wasn't thinking it through i needed the components. i have solved it and am now working on some impulse and momentum stuff with exploding objects
 
I'm sure i will be making another thread in T-15 minutos
 
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