Normal modes: Spring and pendulum

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SUMMARY

The discussion centers on the kinetic energy expression for a mass in a spring-pendulum system, specifically the term ##T_2##. The user asserts that the provided solution for ##T_2 = \frac{m((\dot q+lcos(\theta)\dot \theta)^2 + (lsin(\theta) \dot \theta)^2)}{2}## is accurate, while the original solution is incorrect. The user emphasizes that for small oscillations, this expression can be simplified further, indicating a potential error in the conventional solution provided.

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  • Understanding of classical mechanics, particularly kinetic energy equations.
  • Familiarity with spring-pendulum systems and their dynamics.
  • Knowledge of small angle approximations in oscillatory motion.
  • Basic proficiency in mathematical notation and expressions used in physics.
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  • Review the derivation of kinetic energy in spring-pendulum systems.
  • Study small oscillation approximations in classical mechanics.
  • Explore the implications of incorrect kinetic energy expressions on system behavior.
  • Investigate alternative methods for analyzing oscillatory systems, such as Lagrangian mechanics.
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Students and professionals in physics, particularly those studying mechanics and oscillatory systems, as well as educators looking to clarify concepts related to kinetic energy in spring-pendulum dynamics.

LCSphysicist
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Homework Statement
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I was doing the exercise as follows:
oi.png

I am not sure if you agree with me, but i disagree with the solution given.
I was expecting that the kinect energy of the mass ##m## (##T_2##) should be $$T_2 = \frac{m((\dot q+lcos(\theta)\dot \theta)^2 + (lsin(\theta) \dot \theta)^2)}{2}$$
I could be wrong, of course, but i have tried to figure out my error and was not able to discover. So my guess is that the solution can be wrong.
 
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Your expression for ##T_2## looks correct. For small oscillations it can be simplified a little.

The expression for ##T_2## in the solutions is not correct.
 
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