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Normal probability density function

  1. Oct 2, 2008 #1
    1. The problem statement, all variables and given/known data

    A production line is producing cans of soda where the volume
    of soda in each can produced can be thought of as (approximately) obeying a normal distribution
    with mean 500ml and standard deviation 0.5ml. What percentage of the cans will have more than
    499ml in them?

    Now at my level, the functions to use were simple given to us. The normal probability density function and the standard density function. However, I dont quite understand the idea of P(>499) = 1 - P(<499) = 1 - F(499).

    Could anyone explain why that is?

  2. jcsd
  3. Oct 2, 2008 #2


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    Homework Helper

    I'm not 100% sure of your question, so if this doesn't answer it try again.

    If [tex] F [/tex] is a cumulative distribution function (normal or any other) for a continuous random variable, then for any number [tex] x [/tex], this is true:

    F(x) = \Pr(X \le x )

    This means that whenever you need a probability that is of the form [tex] \Pr(X > x) [/tex], you need to rewrite this in terms of the complement inequality:

    \Pr(X > x) = 1 - \Pr(X \le x)

    This is what happens in your problem, with [tex] x = 499 [/tex]. Is this the type of thing you want?
    Last edited: Oct 2, 2008
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