i have an equation,
f(ρ) = [itex]\rho^{l+1}[/itex][itex]e^{-\rho}[/itex][itex]\upsilon(2\rho)[/itex]
i want to transform it to the following multiplying only the right hand side with [itex](-1)^{2l+1}[/itex][itex](2)^{l+1}[/itex],
f(ρ) = [itex](-1)^{2l+1}[/itex][itex](2\rho)^{l+1}[/itex][itex]e^{-\rho}[/itex][itex]\upsilon(2\rho)[/itex]
is it possible?
i want to use [itex](2\rho)^{l+1}[/itex] instead of [itex]\rho^{l+1}[/itex], because, the normalization coefficient normalizes with respect to ρ whatever the the function f(ρ) is. and [itex](2)^{l+1}[/itex] is not a function of ρ.
i want to multiply by [itex](-1)^{2l+1}[/itex], because i found that if the associated Laguerre polynomial is [itex]AL^{2l+1}_{n+l}(x)[/itex]=[itex]\frac{d^{2l+1}}{dx^{2l+1}}[/itex][itex]L^{}_{n+l}(x)[/itex]. now, in some places, i found A=1 and other places [itex]A=(-1)^{2l+1}[/itex]. besides, is it something related to Condon-Shortley Phase factor?
as after multiplyng by anything which is not a function of [itex]\rho[/itex] will still satisfy the associated laguerre differential equation, can i do this multiplication of [itex](-1)^{2l+1}[/itex][itex](2)^{l+1}[/itex]? thanks.