Why is Wavefunction Normalization on a Ring Done Using dPhi?

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Normalization of a wavefunction for a particle on a ring is typically done using dPhi because the wavefunction is expressed in angular terms rather than linear distance. While it may seem intuitive to include the radial component (r*dPhi), for a ring, r is constant and does not affect the normalization process. The integral of the amplitude squared over the ring must equal 1, and the prefactor is determined by the specific integral used. This approach simplifies the normalization, focusing solely on the angular variable phi. Thus, the normalization effectively captures the wavefunction's behavior on the ring.
M-Speezy
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When normalizing a Wavefunction for a particle on a ring why is the normalization only done as dPhi? It's a particle on a ring, so shouldn't it be r*dPhi? This is my thinking, but I do not find other solutions doing this, just ignoring the r part. I understand that for a ring it's just a constant but it still seems important.
 
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Is the wavefunction expressed in terms of a linear distance or in terms of the angle phi?

If you integrate the amplitude squared over the ring the result has to be 1 - the prefactor will depend on the integral you perform.
 

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