Not a specific problem, just some help with the one step subgroup test

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SUMMARY

The discussion focuses on the one-step subgroup test, a crucial concept in group theory. The example provided illustrates how to demonstrate that the subset H, consisting of multiples of 3 within the group G of integers under addition, is indeed a subgroup. By showing that the sum of any two elements in H, along with the additive inverse, remains in H, the subgroup property is confirmed. This method is essential for validating subgroup criteria in mathematical contexts.

PREREQUISITES
  • Understanding of group theory concepts
  • Familiarity with additive groups
  • Knowledge of subgroup criteria
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the properties of groups in abstract algebra
  • Learn about different subgroup tests, including the two-step subgroup test
  • Explore examples of subgroups in various mathematical structures
  • Investigate the implications of subgroup properties in group homomorphisms
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Mathematics students, particularly those studying abstract algebra, educators teaching group theory, and anyone seeking to deepen their understanding of subgroup tests.

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Homework Statement


i just don't really get the one step subgroup test, which is very important, and something i should understand. can someone walk me through in general how to use the test? maybe give me a simple example? thanks.


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The Attempt at a Solution

 
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Here's a simple example. Let G be the integers with addition as the operation. Let H be the subset of G consisting of the multiples of 3. In G, the [additive] inverse of x is -x.

To show H is a subgroup by that test you must show that if x and y are in H, then x + (-y) is in H.

x in H says x = 3m for some m in G and y in H says y = 3n for some n in G. The inverse of y is then -3n so the expression x + (-y) is just

3m + (-3n) = 3(m + (-n)), using the usual rules. This is a multiple of 3 and therefore in H. So H is a subgroup.
 

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