Not able to understand weight on the surface of earth

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When standing on Earth's surface, two forces act on a person: gravitational force pulling downward and normal force pushing upward. The normal force balances the gravitational force, resulting in no net force, which is why a person does not sink or float. Weight is defined as the force of gravity on an object, while the reading on a scale reflects the normal force, which can vary based on acceleration conditions like being in an elevator. In free fall, an object experiences gravitational acceleration but has no normal force acting on it, leading to a sensation of weightlessness. Thus, weight as measured by scales is not a direct measure of gravitational force but rather the normal force acting on an object.
RohitRmB
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When i am standing on the surface of earth, there are two forces acting on me
1)the gravitational force towards the center of the earth
2)normal force radially oppt to gravity

as the normal force equals gravity, (that is why i don't sink into the ground or start floating in air), so they cancel each other.
now no net force is acting on me.
as gravity force is canceled by normal force, why do we consider weight rather than considering only mass?
 
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When you stand on a scale, the scale measures the normal force only and records this as your weight (this is why your weight as read on a scale can be different if you are for example in an elevator that is accelerating upwards vs accelerating downwards vs in free fall).
 
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So whenever we measure the weight of any object, we just measure the normal force that is been acted on that object.
it has no direct relation with gravity.
Now is my statement correct "When an object is experiencing a free fall, it is getting accelerated due to gravitational force and it also has mass, still it is weightless since there is no normal force acting.
Thus since weight is only a measurement of normal force, it can not give proper idea about (only gravitational force) that is present, but only give a idea about the net force acting on the object.
 
For example, if I am in an elevator accelerating upwards with acceleration ##a## then ##N - mg = ma \Rightarrow N = m(a + g)## so the normal force is the sum of the gravitational force as well as the ##ma## term due to the net acceleration of the elevator. This ##N## is what is read as my weight. Your statement about free fall and weightlessness is correct.
 
RohitRmB said:
So whenever we measure the weight of any object, we just measure the normal force that is been acted on that object.
it has no direct relation with gravity.

Hi RohitRmB. It would be best to avoid the term "normal force" as that is not an applicable term in physics. Weight is the force attributable to gravity acting on a mass. If there is no force opposing your weight, then you accelerate in free fall. If you are held in a fixed position (e.g., by the platform on a set of bathroom scales), then the dial on the scales registers the force it's exerting to hold you up. If there is a force partially opposing your weight, such as air resistance, then your acceleration towards the centre of the Earth is slowed because of the smaller nett force to accelerate your mass.

There is an equation that defines weight: weight = m x[/size] g
 
Sometimes the term "apparent weight" refers to the weight that would be measured by a scale, i.e. the normal force and "weight" refers to the force of gravity on the object. Using this terminology, an astronaut in the international space station has an "apparent weight" which is 0, but the astronaut's "weight" is about 88% of his/her weight on earth.
 
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