MHB Notation for vector coordinates in a given basis

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SUMMARY

This discussion focuses on the computation of vector coordinates during changes of basis and the application of linear operators in linear algebra. Key concepts include expressing "old" coordinates through "new" ones during basis changes and vice versa when applying linear operators. The notation $[v]_{\mathcal{E}}$ is introduced to denote coordinates of vector $v$ in basis $\mathcal{E}$, and the relationship between these coordinates and linear operators is established through equations (1) to (5). The discussion also highlights the limitations of this notation when the basis is not valid.

PREREQUISITES
  • Understanding of linear algebra concepts, specifically basis and coordinates.
  • Familiarity with matrix multiplication and linear transformations.
  • Knowledge of notation for vector coordinates in different bases.
  • Basic principles of category theory as they relate to linear transformations.
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  • Study the properties of linear transformations and their matrices in different bases.
  • Learn about the implications of linear dependence in basis selection.
  • Explore category theory concepts relevant to morphisms and transformations in vector spaces.
  • Investigate alternative notations for expressing vector coordinates and their advantages.
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Students and professionals in mathematics, particularly those specializing in linear algebra, educators teaching vector spaces, and researchers exploring advanced topics in category theory and linear transformations.

Evgeny.Makarov
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Sorry for a long post. I am looking for a clear and concise way to explain how to compute coordinates when changes of basis or linear operators are involved. I would like to avoid the summation notation as much as possible and use the definition of matrix multiplication only in the beginning, when it is indeed necessary. I would like to be able to explain things like the following.

  • Why is it that when a change of basis occurs, we express the "old" coordinates through the "new" ones, but when a linear operator is applied, we express the "new" coordinates through the "old" ones?
  • How to find the matrix of a linear operator in a different basis?
  • Suppose a linear operator $\varphi$ on $\Bbb R^n$ maps a sequence of vectors $\mathcal{A}=(a_1,\dots,a_n)$ to $\mathcal{B}=(b_1,\dots,b_n)$ and $\mathcal{A}$ is linear independent. How to find the matrix of $\varphi$ in basis $\mathcal{E}$ given coordinates of $\mathcal{A}$ and $\mathcal{B}$ in $\mathcal{E}$?

While it is possible to explain the change of basis referring to "new" and "old" coordinates of a single vector in two bases, applying an operator $\varphi$ to a vector $v$ involves four sets of coordinates:
  • coordinates of $v$ in the initial basis $\mathcal{E}$,
  • coordinates of $\varphi v$ in the initial basis $\mathcal{E}$,
  • coordinates of $v$ in the new basis $\varphi\mathcal{E}$ and
  • coordinates of $\varphi v$ in the new basis $\varphi\mathcal{E}$.
It's no longer enough to use $x$ and $x'$ for coordinates. It really helps if we can say precisely which vector in which basis has which coordinates.

A popular idea is to write $[v]_{\mathcal{E}}$ to refer to coordinates of vector $v$ in basis $\mathcal{E}$. Similarly, $[\varphi]_{\mathcal{E}}$ denotes the matrix of $\varphi$ in $\mathcal{E}$ and if $\mathcal{E}'=(e_1',\dots,e_n')$, then $[\mathcal{E}']_{\mathcal{E}}$ is the matrix with columns $[e_1']_{\mathcal{E}},\dots,[e_n']_{\mathcal{E}}$, i.e., the transition matrix from $\mathcal{E}$ to $\mathcal{E}'$. By definition,
\[
[\varphi]_{\mathcal{E}}=[\varphi\mathcal{E}]_{\mathcal{E}}.\tag{1}
\]
Then we can state and prove the following properties.
\begin{align}
&[\mathcal{E}']_{\mathcal{E}}[v]_{\mathcal{E}'}=[v]_{\mathcal{E}}\tag{2}\\
&[v]_{\mathcal{E}}=[\varphi v]_{\mathcal{\varphi E}}\tag{3}
\end{align}

Using this, we can prove that
\[
[\varphi v]_{\mathcal{E}}=[\varphi]_{\mathcal{E}}[v]_{\mathcal{E}}.\tag{4}
\]
Indeed,
\[
[\varphi v]_{\mathcal{E}}\overset{(2)}{=}[\varphi\mathcal{E}]_{\mathcal{E}}[\varphi v]_{\mathcal{\varphi E}}
\overset{(1)}{=}[\varphi]_{\mathcal{E}}[\varphi v]_{\varphi\mathcal{E}}\overset{(3)}{=}[\varphi]_{\mathcal{E}}[v]_{\mathcal{E}}.\tag{5}
\]

For another example, here is the summary of Deveno's explanation that $[\varphi]_{\mathcal{E}'}=[\mathcal{E}]_{\mathcal{E}'}[\varphi]_{\mathcal{E}}[\mathcal{E}']_{\mathcal{E}}$ https://driven2services.com/staging/mh/index.php?posts/55983/. For any $v$,
\[
[\mathcal{E}]_{\mathcal{E}'}[\varphi]_{\mathcal{E}}[\mathcal{E}']_{\mathcal{E}}[v]_{\mathcal{E}'}
\overset{(2)}{=}
[\mathcal{E}]_{\mathcal{E}'}[\varphi]_{\mathcal{E}}[v]_{\mathcal{E}}
\overset{(4)}{=}
[\mathcal{E}]_{\mathcal{E}'}[\varphi v]_{\mathcal{E}}
\overset{(2)}{=}
[\varphi v]_{\mathcal{E}'}.
\]

This notation seems short and expressive, but unfortunately $[v]_{\mathcal{E}}$ does not make sense if $\mathcal{E}$ is not a basis. So if $\varphi$ is not an isomorphism, then the proof (5) does not quite work.

It is possible to define the inverse operation: if $x$ is a column of numbers, then $(x)_{\mathcal{E}}\overset{\text{def}}{=}\mathcal{E}x$ is the linear combination of vectors from $\mathcal{E}$ with coefficients $x$. This operation is well-defined even if $\mathcal{E}$ are linearly dependent. I have not yet finished rewriting (1)-(4) using this notation, but even if this is possible, I am wondering if the proofs would not be too obscure and giving little insight.

How do authors and lecturers usually deal with this? Also, I am wondering if there is a generalization of the operation of taking coordinates. Perhaps coordinates can be thought of as a morphism in category theory from $V\times\dots\times V$ to $V$ taking a basis into a vector. Maybe such a generalization can give a hint for a suitable notation.

Thank you.
 
Physics news on Phys.org
ThePerfectHacker said:
Who needs change-of-basis when one has commutative diagrams?

Suppose $\alpha: \mathcal A \to \mathcal E$ and $\beta: \mathcal B \to \mathcal E$ are the canonical transformations. And suppose $M_\phi$ is the requested matrix.

View attachment 3078

Then:
$$M_\phi = \beta \circ \varphi \circ \alpha^{-1}$$
 

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