- #1

RJLiberator

Gold Member

- 1,095

- 63

**Question:**"Given an electrostatic potential energy of -6.16x10^-18 J and a distance of 1.12x10^-10m, what is the nuclear charge if there is a single electron interacting with the nucleus?"

Okay,

**Equation**:

PE = [K*Q1*Q2]/d

Where K is a constant of 8.99*10^9 J*m/c

d is giving at 1.12*10^-10m

PE is giving at -6.16*10^-18 J

Q1 is giving as the charge of an electron at 1.602 * 10^-19 C

Q2 is what we solve for, which, plugging in the equation is -4.79*10^-19

This equation is easy enough to plug in. HOWEVER, am I answering the equation? Is Q2 = to the nuclear charge? I guess that is where I am confused.

And for Q2 I received a negative charge, I would imagine this is correct since PE is initially negative and the charge of an electron was positive? Or do I have it backwards?

Thank you

Last edited: