Nuclear chemistry reaction question

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SUMMARY

The discussion centers on balancing the nuclear equation ^{98}_{42}Mo + ^{2}_{1}H → ^{1}_{0}n + ?. The initial incorrect answer proposed was ^{99}_{43}Te, which has an atomic number of 52. The correct particle to complete the equation is ^{99}_{43}Tc, which has an atomic number of 43. The confusion arose from a misreading of the periodic table.

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  • Understanding of nuclear equations and balancing
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  • Knowledge of the periodic table
  • Basic concepts of nuclear chemistry
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  • Learn about the process of nuclear decay and its types
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BoundByAxioms
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Homework Statement


Complete and balance the following nuclear equations by supplying the missing particle.^{98}_{42}Mo+^{2}_{1}H\rightarrow^{1}_{0}n+?

Homework Equations


The Attempt at a Solution



I would think that the answer would just be ^{99}_{43}Te. It seems correct, since everything adds up nicely, but apparently my answer is incorrect. Am I missing something?
 
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BoundByAxioms said:

Homework Statement


Complete and balance the following nuclear equations by supplying the missing particle.^{98}_{42}Mo+^{2}_{1}H\rightarrow^{1}_{0}n+?


Homework Equations





The Attempt at a Solution



I would think that the answer would just be ^{99}_{43}Te. It seems correct, since everything adds up nicely, but apparently my answer is incorrect. Am I missing something?


It looks like your math is right, but you picked the wrong element...Te (Tellurium) has an atomic number of 52. Try ^{99}_{43}Tc.
 
Oh my goodness, thank you! I can't believe I did that. I think I glanced at my periodic table too quickly, and read that "c" as an "e". Thank you, that was indeed the correct answer.
 

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