Nuclear Radius Equation R = R0 A^(1/3)

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ZedCar
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If using the nuclear radius equation:

R = R0 A^(1/3)

as shown half-way down this page:
http://en.wikipedia.org/wiki/Atomic_nucleus

r0 = 1.25 fm = 1.25 × 10−15 m

Is this value for r0 always this value, irrespective of the material in question? For example, if it was gold, or some other material?

Thanks
 
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Approximately. That equation is true for any substance of constant density. That's a pretty good assumption for cold nuclear matter.
 
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Thanks Vanadium 50.