Nucleon in Inifinte Square Well

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SUMMARY

The discussion centers on calculating the normalized wave functions and energies of the four lowest states for a nucleon in an infinite square well with a radius of 2.8E-13 cm. The wave function is correctly expressed as ψ(x) = √(2/a) sin(nπ/a x), leading to energy levels defined by E_n = (n²π²ħ²)/(2ma²). Here, 'a' is determined to be 5.6E-13 cm, and 'm' represents the nucleon mass. The calculations presented are valid and align with quantum mechanics principles.

PREREQUISITES
  • Understanding of quantum mechanics principles
  • Familiarity with wave functions and normalization
  • Knowledge of the Schrödinger equation
  • Basic grasp of particle physics, specifically nucleon properties
NEXT STEPS
  • Study the derivation of the Schrödinger equation for one-dimensional potentials
  • Explore quantum mechanics applications in particle confinement
  • Learn about the implications of quantum states in nuclear physics
  • Investigate the concept of quantum tunneling and its relevance to nucleons
USEFUL FOR

Students and professionals in physics, particularly those focusing on quantum mechanics and nuclear physics, will benefit from this discussion.

atomicpedals
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Homework Statement



Assuming an infinite square well of radius 2.8E-13cm, find the normalized wave functions and the energies of the four lowest states for a nucleon.

2. The attempt at a solution

I want to say that the wave function is \psi (x) = \sqrt{\frac{2}{a}} sin(\frac{n \pi}{a} x). Which then leads to possible energies of E_{n}=\frac{n^{2} \pi^{2} \hbar^{2}}{2 m a^{2}}. Where in this case a = 2(2.8 \times 10^{-13}) = 5.6 \times 10^{-13}. And m would be the nucleon mass. Does this work?
 
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I think I've convinced myself this is valid; or at least not totally off base.
 

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