Null-homotopic, Retracts: Review for Prelims.

1. Aug 24, 2011

WWGD

Hi, Everyone:

I am trying to help someone with their prelims, but ended up needing some help myself:

1)Show that every map f: CP^2--->S^1 x S^1 x S^1 is nullhomotopic

2)Is the wedge RP^2 \/RP^2 a retract of RP^2 x RP^2 ?

For 1), I think we need to use the cell decomposition for CP^2 somehow, or just use
the fact that the 3rd homology ( 3 being odd ) is 0 , so that the induced map on
3rd homology must be trivial.

For 2, all I can think is that if the wedge were a retract, then it would be homotopic
to the product , so that all homology/homotopy groups would be equal. I think the
answer is no, since the homology of the wedge is the free product, but the
homology of the product is given by Kunneth's theorem, and we get different groups.

Does this work? Any ideas?

Thanks.

2. Aug 24, 2011

Bacle

I think for #1 , you can use lifting of maps ; R^3 is a covering space for the 3-torus
maps lift if these maps satisfy a condition on the pushforward of the fundamental groups;
if the maps lift into R^3, then these maps are trivial, since R^3 is contractible, and
every map into a contractible space is trivial.

3. Aug 25, 2011

lavinia

isn't the fundamental group of the wedge of two projective planes the free product of Z/2Z with Z/2Z where the fundamental group of the product is Z/2Z x Z/2Z?

no composition of group homomorphisms Z/2ZvZ/2Z -> Z/2Z x Z/2Z -> Z/2ZvZ/2Z
can be the identity.