Nullity of a Matrix: Find the Dimension V & Its Result

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The discussion focuses on determining the nullity of a linear transformation T applied to a 3x3 matrix M, defined by T(M) = M + M^t. The nullity, which is the dimension of the null space of T, is derived from the conditions imposed by T on the entries of M. Specifically, the transformation leads to six constraints on the matrix, indicating that the null space consists of all anti-symmetric 3x3 matrices. Consequently, the nullity of T is 3, as the dimension of the space of all 3x3 matrices is 9, and 6 conditions reduce the dimension accordingly.

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Punkyc7
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Let M be a 3x3 matrix with entries from the Reals

Let T:V-W be linear


such that

T(M)= M+M^t


what is the nullity


we know

dimN(T)+dimR(T)=Dim V


im not sure how would figure this out, if the number were abritary numbers couldn't you have a nullity of 9 to 0?
 
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The nullity is the dimension of the null space. If M is in the null space of T, what does T(M) equal?
 
You are given that T maps M to M+ Mt.

That is, T maps
[tex]\begin{bmatrix}a & b & c \\ d & e & f \\ g & h & i\end{bmatrix}[/tex]
to
[tex]\begin{bmatrix}2a & b+ d & c+ g \\ b+ d & 2e & f+ h \\ c+ g & f+h & 2i\end{bmatrix}[/tex]

So any matrix in the nullspace of T must satisfy 2a= 0, b+ d= 0, c+ g= 0, 2e= 0, c+ g= 0, 2i= 0. The dimension of the space of all 3 by 3 matrices is 9, of course, but now we are imposing 6 conditions on it.

(In fact, the nullspace of T is exactly the space of all anti-symmetric 3 by 3 matrices.)
 

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