- #1
konichiwa2x
- 81
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A 5kg block is resting on the top right hand corner of a 10kg block. The length of the top of the 10kg block is 10m. Find the time taken by the 5kg block on top to slide of the 10kg block completely if the 10kg block is accelerating at 5m/s^2.
My work:
aB = accleration of the 5kg block
aA = acceleratipon of the 10kg block
If the 10kg block is accelerating to the right, then a pseudo force must be acting on the 5kg block on it in the opposite direction,
so fp = 5aB
aB = 5
aB - aA = -10
-10 = 1/2(-10)t^2
t = (2)^1/2
where am i going wrong? My book says 2 seconds is the correct answer. Please help
My work:
aB = accleration of the 5kg block
aA = acceleratipon of the 10kg block
If the 10kg block is accelerating to the right, then a pseudo force must be acting on the 5kg block on it in the opposite direction,
so fp = 5aB
aB = 5
aB - aA = -10
-10 = 1/2(-10)t^2
t = (2)^1/2
where am i going wrong? My book says 2 seconds is the correct answer. Please help