O-H Bonding (and ion dissociation)

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Discussion Overview

The discussion revolves around the bonding characteristics of O-H bonds, particularly in the context of water formation during hydrogen combustion and the dissociation of hydroxide ions in solution. Participants explore the role of electronegativity in bond stability and the behavior of NaOH in different solvents.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant suggests that the stability of the O-H bond in water formation is due to the electronegativity difference between oxygen and hydrogen.
  • Another participant argues that while electronegativity indicates electron transfer and bond polarity, it does not directly correlate with bond stability, which is influenced by the energy levels of molecular bonds compared to atomic orbitals.
  • There is a question about whether the OH- ion remains intact in solution due to electronegativity differences and energy considerations.
  • One participant mentions that the OH- group can exchange hydrogen and oxygen with the solvent, indicating a dynamic interaction in solution.
  • A participant inquires about the dissociation of NaOH in a polar solvent like THF and whether it occurs similarly to its dissociation in water.
  • Another participant confirms that NaOH does dissociate in THF but notes that the interactions differ due to the absence of hydrogen bonding in aprotic solvents.

Areas of Agreement / Disagreement

Participants express differing views on the relationship between electronegativity and bond stability, and there is no consensus on how NaOH behaves in various solvents, indicating ongoing debate and exploration of these concepts.

Contextual Notes

Participants discuss the implications of electronegativity and bond dynamics without resolving the complexities of these interactions or providing definitive equations for calculations related to dissociation energy.

pzona
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This is probably something I should know, but I don't want to wait and ask my professor. In the combustion of H2, assuming O2 is plentiful enough not to be a limiting reactant, H2O forms as a result of the O-H bond being more stable than the bonds between two H or two O. Is this due to the electronegativity difference?

On a related note, although the answer might be the same, in a hydroxide's dissociation in a solution (let's say the dissociation of NaOH into Na^{+} and OH^{-} in water), the OH^{-} ion remains held together because of this bond, which is due to the difference in electronegativities, correct (aside from the fact that there isn't enough energy to break it)? And if so, what equation would I use to calculate the temperature or kinetic energy of the water needed to dissociate it further into H^{+} and O^{2-}?
 
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pzona said:
This is probably something I should know, but I don't want to wait and ask my professor. In the combustion of H2, assuming O2 is plentiful enough not to be a limiting reactant, H2O forms as a result of the O-H bond being more stable than the bonds between two H or two O. Is this due to the electronegativity difference?

The electronegativity difference will tell you which atom gives an electron and which accepts the electron and perhaps the polarity of the resulting bond but is doesn't say anything about stability per se. It has to do with the energy level of the molecular bond vs the energy level of the individual atomic orbitals.

On a related note, although the answer might be the same, in a hydroxide's dissociation in a solution (let's say the dissociation of NaOH into Na^{+} and OH^{-} in water), the OH^{-} ion remains held together because of this bond, which is due to the difference in electronegativities, correct (aside from the fact that there isn't enough energy to break it)?

Not really... that OH- group swaps out that hydrogen with the solvent. In this case, it can also swap out the oxygen!

for example:

OH- + HOH <------> HOH + OH-
or
OH- + HOH <--------> OH- + HOH
 
Okay that leads me to another question then. In another polar solvent, such as THF, does the NaOH dissociate in the same way? And if so why?
 
It still dissociates, although solvation is generally different for ionic compounds in protic vs. aprotic solvents since aprotic solvents don't have hydrogens that can participate in hydrogen bonding..
 
pzona said:
Okay that leads me to another question then. In another polar solvent, such as THF, does the NaOH dissociate in the same way? And if so why?

NaOH ionizes into Na+ and OH- but the hydrogen and the oxygen do not swap out with the oxygen and hydrogens of THF.
 

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