Object and a 3d direction vector

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    3d Direction Vector
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SUMMARY

The discussion focuses on determining whether a point X is located below a plane defined by a 3D direction vector and position. A plane in three dimensions can be represented by the equation Ax + By + Cz < D. To ascertain if a point (x, y, z) is below this plane, the condition z < (D - Ax - By) / C must be satisfied, with C being positive for the inequality to hold true. The conversation clarifies the distinction between a line in 2D and a plane in 3D, emphasizing the mathematical relationships involved.

PREREQUISITES
  • Understanding of vector mathematics in three dimensions
  • Familiarity with the equation of a plane Ax + By + Cz = D
  • Basic knowledge of inequalities and their graphical interpretations
  • Experience with coordinate systems in 3D space
NEXT STEPS
  • Study the derivation and applications of the plane equation in 3D geometry
  • Learn about vector operations and their implications in spatial calculations
  • Explore graphical representations of planes and points in 3D space
  • Investigate computational geometry techniques for point-plane relationships
USEFUL FOR

Mathematicians, computer graphics developers, and anyone involved in 3D modeling or spatial analysis will benefit from this discussion.

badescuga
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i have an object and a 3d direction vector and position for it . I would like to know how do i determine if a certain point X is in the space below the plan determined by my direction ?

Here is an image that i have drawn to make it more clear . In this image I've made the vector 2d

http://yfrog.com/53imgukp

Please Help!Regards,
Aleandru Badescu
 
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Do you mean a "plane" or a "line"?

A single vector determines a line, Ax+ By= C, in two dimensions. A point (x,y) is on that line if y= (C- Ax)/B. It is "below" that line if y< (C- Ax)/B. If B is positive (and you can always arrange for B to be positive by multiplying the entire equation by -1 if necesary) that is the same as Ax+ By< C.

In three dimensions, a single vector <A, B, C>, determines a plane Ax+ By+ Cz< D. (x, y, z) is "below" that line if z< (D- Ax- By)/C. Again, if C is positive, that is the same as Ax+ By+ Cz< D.
 

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