Object on a plane (equilibrium problem)

  • Thread starter Thread starter ZacBones
  • Start date Start date
  • Tags Tags
    Plane
Click For Summary
SUMMARY

The discussion focuses on solving an equilibrium problem involving a 1350 kg car at rest on a plane surface, with a specified normal vector of 0.231i + 0.923j + 0.308k. Participants clarify that the weight vector is W = 1350 * 9.81j, and the normal force can be expressed as FN = 0.231|FN|i + 0.923|FN|j + 0.308|FN|k. The solution involves calculating the components of the weight vector relative to the normal vector and determining the frictional force necessary to maintain equilibrium.

PREREQUISITES
  • Understanding of vector components in physics
  • Knowledge of equilibrium conditions and force summation
  • Familiarity with scalar products and their application in physics
  • Ability to solve systems of equations
NEXT STEPS
  • Learn how to compute scalar products in vector analysis
  • Study the principles of static equilibrium in physics
  • Explore methods for resolving forces into components
  • Investigate frictional force calculations in inclined planes
USEFUL FOR

Students in physics, particularly those studying mechanics, engineers dealing with force analysis, and anyone interested in understanding equilibrium problems involving forces on inclined surfaces.

ZacBones
Messages
2
Reaction score
0

Homework Statement



A 1350kg car is at rest on a plane surface.
The unit vector normal to the surface is: 0.231i + 0.923j + 0.308k.
The y-axis points upwards.

Find the magnitude of the normal and friction forces the car's wheels exert on the plane.

Homework Equations



[tex]\sum[/tex] F = 0.

The Attempt at a Solution



--The weight has the vector W = 1350*9.81i
--The normal force has the vector FN = 0.231|FN|i + 0.923|FN|j + 0.308|FN|k

I also need to express the frictional force as a vector. I know I can find an infinite number of vectors normal to the given vector, but I don't see how I am to choose which is the right one. Mentally, I imagine the car tending to slide "down" the slope relative to its incline, but I'm not sure how to turn this intuition into a vector involving the friction force. Moreover, wouldn't the slide direction depend on the relative strength of the gravitational vs. the normal force?

Even if I found that, I would still need to solve a system of three equations (resulting from setting the sum of components of the force vectors equal to zero). This makes me question my strategy since there are only two unknowns.

I feel like I am missing something obvious here, or that I'm over-complicating the problem. Can anyone clue me into where I am going wrong?

Thanks,
-Zac
 
Physics news on Phys.org
First: the y-axis points upward, and the unit vector in the y direction is usually called j. So the weight is W = 1350*9.81 j.

The weight has a component normal to the surface, parallel with the normal of the plane. You can find this component from the scalar product of the weight with the normal vector. This component cancels with FN, the force between the car and the surface.

The other component of the weight is parallel with the slope. You need a frictional force of equal magnitude and opposite sign to cancel it.

ehild
 
Thanks for the reply. Typically I solve these sorts of problems by solving the system of component equations summed to zero...it didn't occur to me to split the forces the way you suggested.

It also took me forever to remember how to compute the gradient of a plane and then find a line parallel to the plane and following the gradient, but once I did, I was *finally* able to solve for the frictional force.

(Next time I ask something I'll use angle-bracket notation instead of i/j/k in order to avoid typos.)

Thanks,
-Zac
 

Similar threads

  • · Replies 11 ·
Replies
11
Views
4K
Replies
6
Views
3K
  • · Replies 27 ·
Replies
27
Views
5K
  • · Replies 22 ·
Replies
22
Views
21K
  • · Replies 7 ·
Replies
7
Views
4K
Replies
5
Views
2K
Replies
5
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 3 ·
Replies
3
Views
4K