1. The problem statement, all variables and given/known data A board that is of length L = 6.0 m and weight W = 335.7 N rests on the ground and against a frictionless contact at the top of a wall of height h = 2 m (see figure). The board does not move for any value of greater than or equal to 65 degrees but slides along the floor if <65 degrees. Find the coefficient of static friction between the board and the floor. 2. Relevant equations Σt=0 F(roller)=Fs Fn=W Fs=Fn(μ) Horizontal Forces. F(roller) is the horizontal force are the roller point. Fs is the force of friction at the point of contact with the ground and direction towards the wall Vertical Forces. Fn is the normal force from the point of contact. W is the force of the rod. 3. The attempt at a solution Fn=335.7 Fs=335.7μ F(roller)=335.7μ Σt=0=Fs*d+Fn*d+W*d1-F(rol)*d2 d=0,[Fs*d+Fn*d]=0 Σt=0=W*d1-F(rol)*d2 F(rol)*d2, d2=h Fr(2)=W*d1 W*d1, d1= L/2cos65 [335.7(6/2)(cos65)]/2=Fr Fr=335.7μ ( [335.7(6/2)(cos65)]/2 )/335.7 =μ Am I making a huge mistake with my thought process?