Oblique shock waves: how to find the wedge angle for trailing shock?

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SUMMARY

The discussion centers on determining the wedge angle for oblique shock waves, specifically noting a wedge angle of 6 degrees at the trailing edge of a body. The relationship between the flow turning angle and the oblique shock wave angle is established through the θ - β relationships. The inquiry also addresses how changes in the body shape, such as a flat top, may affect the calculation of the effective wedge angle. Understanding these principles is crucial for analyzing supersonic and hypersonic flow behavior.

PREREQUISITES
  • Understanding of oblique shock wave theory
  • Familiarity with θ - β relationships in fluid dynamics
  • Knowledge of supersonic and hypersonic aerodynamics
  • Basic principles of flow turning and shock wave interactions
NEXT STEPS
  • Study the derivation and application of the θ - β relationships in oblique shock wave analysis
  • Explore the effects of body geometry on shock wave behavior in supersonic flows
  • Investigate computational fluid dynamics (CFD) tools for simulating oblique shock waves
  • Learn about the mathematical modeling of shock waves in varying flow conditions
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Aerodynamics engineers, fluid dynamics researchers, and students studying supersonic and hypersonic flow phenomena will benefit from this discussion.

Master1022
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Homework Statement
How can we find the wedge angle for the trailing shock wave?
Relevant Equations
Shock waves
Hi,

I have a question regarding oblique shockwaves.

Question: How can we determine what the wedge angle is for the shockwave in a situation?

Context: This problem here shows an oblique shock wave on the trailing edge of the body and it simply states that the wedge angle is 6 degrees. Why is this the case? Is there a general principle/method to figure these out? What if the body was completely flat on top (i.e so the body is no longer symmetric); does that change the process of knowing what the effective 'wedge angle'?

Note that the leading one makes sense to me as I can see that the flow is being turned by 6 degrees and thus that can be used in the ## \theta - \beta ## relationships to find the angle of the oblique shock wave...

Screen Shot 2021-03-01 at 8.49.54 PM.png


Any help would be greatly appreciated. Please let me know if this is in the wrong forum.
 
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My understanding of supersonic / hypersonic travel is that the atmosphere acts like an incompressible liquid or solid. In aerodynamics lift is classically represented by suction on the top trailing edge of the wing this is perhaps similar to the reason for the "oblique shock wave on the trailing edge of the body". Effectively the trailing shock wave would be similar to suction or cavitation. Not sure about the mathematical version of the explanation.
 
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