Obtaining Directions Vector for Perpendicular Lines

  • Thread starter Thread starter Miike012
  • Start date Start date
  • Tags Tags
    Vector
Click For Summary
SUMMARY

The discussion centers on the geometric relationship between a line and a plane in three-dimensional space. Specifically, it addresses a line defined by the parametric equations x = 1 + t, y = 1 - t, z = 2t, which has a direction vector of <1, -1, 2>. The line is stated to be parallel to the plane defined by the equation x + y + z = 2. It is confirmed that if a line is parallel to a plane, it must be perpendicular to the plane's normal vector, which is <1, 1, 1> in this case. The discussion emphasizes the importance of visualizing these relationships using physical models, such as a sheet of paper and a pen.

PREREQUISITES
  • Understanding of vector representation in three-dimensional space
  • Knowledge of the equation of a plane in the form Ax + By + Cz = D
  • Familiarity with parametric equations of lines
  • Basic concepts of perpendicularity and parallelism in geometry
NEXT STEPS
  • Study the properties of normal vectors in relation to planes
  • Explore the geometric interpretation of vector operations
  • Learn about the implications of parallel and perpendicular lines in 3D space
  • Investigate the use of physical models to visualize geometric concepts
USEFUL FOR

Students of geometry, educators teaching three-dimensional space concepts, and anyone interested in the relationships between lines and planes in vector mathematics.

Miike012
Messages
1,009
Reaction score
0
Refer to paint document for question

The questions says that the line is parallel to plane x + y + z = 2 and perpendicular to the line x = 1 + t, y = 1 -t, z = 2t

My question is if the line is parallel to the plane it must be perpindicular to the planes normal, right? If this is true shouldn't the vector representation of the line x = 1 + t, y = 1 -t, z = 2t which is <1,-1,2> be parallel to the planes normal?
 

Attachments

  • Question.jpg
    Question.jpg
    4.5 KB · Views: 431
Physics news on Phys.org
My question is if the line is parallel to the plane it must be perpindicular to the planes normal, right? If this is true shouldn't the vector representation of the line x = 1 + t, y = 1 -t, z = 2t which is <1,-1,2> be parallel to the planes normal?
No. Something you can see with a model - use a sheet of paper to represent the plane, draw a line on the sheet - that line is parallel to the plane right? Now use your pen to represent another line ... place the pen so it is perpendicular to the line in the paper.

Your initial impulse will be to put the pen perpendicular to the paper - well done - however, see if you can put it at slant to the paper and still keep it perpendicular to the line in the paper.
 

Similar threads

  • · Replies 9 ·
Replies
9
Views
1K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 21 ·
Replies
21
Views
4K
Replies
4
Views
5K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
6
Views
4K
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K