ODEs- How to annihilate ln(x) ?

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Homework Help Overview

The discussion revolves around the problem of finding an annihilator for the function ln(x) within the context of ordinary differential equations (ODEs). Participants explore various approaches to identify a suitable annihilator and discuss the implications of different methods.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants suggest different forms for the annihilator, including polynomial expressions involving derivatives. There is a discussion about the validity of these forms, particularly in relation to the nature of the differential equation being addressed.

Discussion Status

The conversation is active, with participants offering suggestions and questioning the assumptions behind their proposed methods. Some guidance has been provided regarding the transformation of the equation and the application of the method of annihilators, though there is no explicit consensus on the best approach.

Contextual Notes

There are discussions about the limitations of using certain forms of annihilators, particularly those involving non-constant coefficients. The participants also consider the implications of transforming the equation to apply methods typically reserved for constant coefficient differential equations.

Roni1985
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Homework Statement



I need to annihilate ln(x)

Homework Equations





The Attempt at a Solution



my try was saying that this is a Euler equation with
r1=r2=0
c1=0 and c2=1
so the annihilator should be D^2
but I don't think it works.

Any other suggestions ?

Thanks.
 
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How about [itex](D+xD^2)[/itex]?
 
gabbagabbahey said:
How about [itex](D+xD^2)[/itex]?

Yep, it works :\
thanks.
But, how did you get it ?

Roni.
 
I got it by inspection, but if you are looking for a general method, I would say begin by finding [itex]Dy(x)[/itex] and [itex]D^2y(x)[/itex] and seeing if they are proportional to each other.

EDIT: Actually, I don't think you can claim that this is a valid annhilator, since it involves [itex]x[/itex] and is not just a polynomial (with constant coefficients) in [itex]D[/itex]
 
gabbagabbahey said:
I got it by inspection, but if you are looking for a general method, I would say begin by finding [itex]Dy(x)[/itex] and [itex]D^2y(x)[/itex] and seeing if they are proportional to each other.

I see...
thanks very much for the help...
 
gabbagabbahey said:
I got it by inspection, but if you are looking for a general method, I would say begin by finding [itex]Dy(x)[/itex] and [itex]D^2y(x)[/itex] and seeing if they are proportional to each other.
...
Would it be accurate to say that we check if a finite amount of derivatives are a linear combination?
 
The method of annihilators is a method for solving constant coefficient DE's. An Euler DE is not that type, but it can be transformed into a constant coefficient DE by a change of variables. Then you can use the method of annihilators on the transformed equation and transform the answer back to solve your original Euler DE. The change of variables you need is t = ln(x). Using a dot for differentiation with respect to t you get, using t = ln(x):

[tex]\frac{dy}{dx}=\frac{dy}{dt}\frac{dt}{dx} = \dot y\frac 1 x[/tex]

[tex]\frac{d^2y}{dx^2}= -\frac 1 {x^2}\dot y + \frac 1 x \frac{d\dot y}{dt}\frac{dt}{dx}<br /> =-\frac 1 {x^2}\dot y+\frac 1{x^2}\ddot y[/tex]

When you substitute these into the left side of your Euler equation you will be left with a constant coefficient equation for y as a function of t. You will need to substitute x = et in the right side too. Solve that by annihilators and substitute t = ln(x) to get your final answer.
 
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