- #1

smd1991

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1) You have a potential difference of 6 volts. How much work is done to transfer .19 coulombs of charge through it? Answer in units of Jules.

2) Through what potential difference would an electron need to be accelerated for it to achieve a speed of 6% of the speed of light(2.99792e8), starting from rest? Answer in units of Volts.

W=Fd=qEd

PE=-W=-qEd

Potential difference between two points is V=PE/q

q=charge in coulombs.

w=work

PE=potential energy

d=distance

E=field

v=potential difference

2) Through what potential difference would an electron need to be accelerated for it to achieve a speed of 6% of the speed of light(2.99792e8), starting from rest? Answer in units of Volts.

W=Fd=qEd

PE=-W=-qEd

Potential difference between two points is V=PE/q

q=charge in coulombs.

w=work

PE=potential energy

d=distance

E=field

v=potential difference