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Homework Help: Oh really? potential difference sucks!

  1. Mar 2, 2008 #1
    1) You have a potential difference of 6 volts. How much work is done to transfer .19 coulombs of charge through it? Answer in units of Jules.

    2) Through what potential difference would an electron need to be accelerated for it to achieve a speed of 6% of the speed of light(2.99792e8), starting from rest? Answer in units of Volts.

    W=Fd=qEd
    PE=-W=-qEd
    Potential difference between two points is V=PE/q

    q=charge in coulombs.
    w=work
    PE=potential energy
    d=distance
    E=field
    v=potential difference
     

    Attached Files:

  2. jcsd
  3. Mar 3, 2008 #2

    Shooting Star

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    Homework Helper

    I can't see the attachment yet, but for (1), you can use W=qV.

    Now, (2) should be clear.
     
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