1) You have a potential difference of 6 volts. How much work is done to transfer .19 coulombs of charge through it? Answer in units of Jules.(adsbygoogle = window.adsbygoogle || []).push({});

2) Through what potential difference would an electron need to be accelerated for it to achieve a speed of 6% of the speed of light(2.99792e8), starting from rest? Answer in units of Volts.

W=Fd=qEd

PE=-W=-qEd

Potential difference between two points is V=PE/q

q=charge in coulombs.

w=work

PE=potential energy

d=distance

E=field

v=potential difference

1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

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# Oh jesus. potential difference problems help per favore!

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