What I was trying to say in the above, and I was trying to address a beginner audience, is that "white" light is not a single wavelength. The concept is simple enough that I think the more advanced should be able to see what I was referring to, and could perhaps say it in a better way, rather than putting a lot of effort into finding a lot of fault with the statement. I did think it was necessary for completeness to mention white light in this thread.
The concept of monochromatic (single wavelength sources of some ## \lambda ## around a narrow ## \Delta \lambda ## ) is also needed early-on for students. I do think I am presenting this concept in a reasonably good way, but
@sophiecentaur , you may disagree. Both in college and at the workplace I did a fair amount of spectroscopy work, and for doing any kind of interference, such as from a diffraction grating or a thin film interference filter, one works with single wavelengths in the calculations, because light of two different wavelengths, except in rare cases, does not interfere. This is also a concept that is taught early-on in the Optics courses.
Edit: and to say the above in another way, there is no such thing as "monochromatic" white light, where monochromatic means single wavelength. Red, blue, green, yellow, orange, and violet can all come in monochromatic form, but white light can not. It was shown in the OP that yellow can have a monochromatic form with ## \lambda \approx 585 ## nm, or it can come as a mixture of red and green light, but white light is never of a monochromatic form. I thought this is indeed a useful concept for the beginner=I thought it should have been fairly clear what I was trying to get across to the reader.
In any case, it is worthwhile to get some feedback in an ordinary thread, rather than to try to write the topic up as an Insights article, and then find there are a couple who disagree, perhaps even strongly, with how it is presented.