One-Dimensional Motion with Constant Acceleration

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Homework Help Overview

The problem involves a rock released from rest at the top of a cliff, accelerating downward under the influence of gravity. The question seeks to determine the distance traveled by the rock during the first 7 seconds of free fall, assuming no air resistance.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the use of the equation for motion, questioning the role of initial position in the context of the problem. There is an exploration of why initial position appears to be disregarded in calculations.

Discussion Status

Some participants have offered insights into the flexibility of choosing a reference point for position and the implications of initial velocity being zero. There is an ongoing examination of the assumptions made in applying the motion equations.

Contextual Notes

Participants note that the initial position cannot be zero since the rock is dropped from a height, leading to discussions about how to define the reference point for calculations.

PhysicallyAbel
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Homework Statement


A rock is released from rest from the top of a very high cliff, and accelerates downward at g.
Approximately how far does the rock travel in the first 7 seconds of its free-fall? (Assume no air friction.)

Homework Equations


X=Xo+volt+1/2AT^2

The Attempt at a Solution


I understand how to work out the problem, but I do not know why it works. You simply substitute the numbers into get the distance. But for some reason, you are not given (nor do you use) initial position like the equation calls for. Can someone explain why it's simply thrown away? The initial position can't be 0, as it's being dropped from a mountain.[/B]
 
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PhysicallyAbel said:

Homework Statement


A rock is released from rest from the top of a very high cliff, and accelerates downward at g.
Approximately how far does the rock travel in the first 7 seconds of its free-fall? (Assume no air friction.)

Homework Equations


X=Xo+volt+1/2AT^2

The Attempt at a Solution


I understand how to work out the problem, but I do not know why it works. You simply substitute the numbers into get the distance. But for some reason, you are not given (nor do you use) initial position like the equation calls for. Can someone explain why it's simply thrown away? The initial position can't be 0, as it's being dropped from a mountain.[/B]

The question is asking how far the rock travels. That's the difference between the final position and the initial position. ##x_0## cancels when you take the difference.
 
It sounds like you are memorizing formulas without really understanding them. That's a bad idea. You are free to take the "0" point any where you want. I suggest taking x= 0 at the top of the cliff. Further, the fact that rock is "released from rest" tells you that the initial velocity is 0. Finally, you can take the acceleration due to gravity to be either negative or positive- as long as you interpret the results in the same way- you are free to choose "positive" or "negative" either up or down.
 
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You can ignore the mountain altogether : you have a ( constant ) acceleration rate, a starting velocity (u = 0) and a time ( 7 seconds ), so use Newtons rules of motion.
 

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