One last log law question. little more trickier.

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SUMMARY

The discussion centers on evaluating the expression \(10^{\log_{10^2}4}\). The user initially solved \(10^{\log_{100}4}\) and obtained 2 by applying logarithmic laws. They sought clarification on manipulating the exponent in the expression \(10^{\log_{10^2}4}\) and expressed confusion regarding the bases of 10 and 4. The solution involves using the change of base formula, specifically \(\log_{100} x = \frac{\log_{10} x}{\log_{10} 100}\), to simplify the evaluation process.

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Homework Statement


10^{log_{100}4} Evaluate.

I'm on a school computer, i cannot see TEX images. Sorry if their not 100% correct.[/color]

The Attempt at a Solution



I solved this answer, and got 2. i did this by making the above equation:

100^\frac{1}{2}(log_{100}4)
then using a log law to get 4 to the power of 1/2 and solved for 2 using the "double base rule"

I was told their was a way to do the same thing, but for the exponent and not the base.

how do you solve: 10^{log_{10^2}4} somehow it still gives a power of 1/2 to the value 4 but i don't understand how to put it there.

i tried putting it in exponential form:

10^{2x} = 4

and i guess ed by dividing both exponents by 2 to get:

10^x = 4^{\frac{1}{2}}

but 10 and 4 arent the same base. Is this correct?

Thanks,
Senjai
 
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Maybe you can use the identity:

\log_{100} x=\frac{\log_{10} x}{\log_{10} 100}

?
 
And in Donaldos's formula, log10100 = 2.
 

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