Op amp transfer function determination ()

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The discussion focuses on determining the transfer function of an op-amp circuit that includes an active low-pass filter. The user correctly identifies the relationship Vout/Vs = -(Zf/Zs), with Zf and Zs defined in terms of resistances and capacitances. However, they express confusion about incorporating the second input source, V1, into the transfer function. The conversation highlights the need to derive two separate transfer functions for the inverting and non-inverting configurations. Ultimately, the user seeks assistance in combining these functions to find the overall output, Vout = Vout1 - Vout2.
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Hey guys, need help with a problem here.

Sorry for the quality of the image.

2q0r6tg.jpg


I understand that above the op-amp, is the active low pass filter. So if I were to figure that out with respect to V2 and Vout, it would just be

Vout/Vs = -(Zf/Zs)

where

Zf = (Rf/(1+jwCfRf))
Zs = Rs

But I don't understand how the bottom setup comes into the equation. I realize it must also be a filter and should be solved wrt V1.

And I am asked to find the transfer function Vout/V1-V2.

All help would be greatly appreciated.
 
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Because you have two input sources you can derive two different transfer functions (one inverting and the other one non-inverting).
And - as a second step - it should not be a problem to substract both functions Vout=Vout1-Vout2.
 

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