Optics, the resulting power of the lens .?

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The discussion centers on calculating the resulting power of a thin lens submerged in a liquid with a refractive index of 1.6. The lens has a front surface power of +11 diopters and a back surface power of -6 diopters, with a material refractive index of 1.5. The resulting power of the lens when submerged is determined to be +1 diopter. This conclusion is reached by applying the lens maker's formula and considering the effect of the surrounding medium on the lens's optical power.

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mero coactail
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optics, the resulting power of the lens...??

a thin lens , made of refractive index 1.5,has a front surface +11 d power and back surface -6d ..if this lens is submerged in a liquid of refractive index 1.6, the resulting power of the lens is...

a)-1 dioptre

b)+1 dioptre

c)-5 dioptre

d)+5 dioptre

pleasezzz answer ,,,and why please ..its emergency:frown:..
 
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hi mero coactail! welcome to pf! :wink:
mero coactail said:
a thin lens , made of refractive index 1.5,has a front surface +11 d power and back surface -6d ..if this lens is submerged in a liquid of refractive index 1.6, the resulting power of the lens is...

a)-1 dioptre

b)+1 dioptre

c)-5 dioptre

d)+5 dioptre

pleasezzz answer ,,,and why please ..its emergency:frown:..

what equations are relevant here?

show us what you've tried, and where you're stuck, and then we'll know how to help! :smile:
 

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