Optimal Flight Path for Eastward Destination with Wind Speed and Direction

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SUMMARY

The discussion centers on calculating the optimal flight path for a pilot flying due east while contending with a northeast wind blowing at 42.5 km/h. The plane's maximum speed in still air is 140 km/h. To achieve the desired eastward trajectory, the pilot must adjust the heading to counteract the wind's influence, resulting in a different effective speed toward the destination. The key is to determine the angle θ at which the plane should be pointed to ensure the resultant vector aligns directly eastward.

PREREQUISITES
  • Understanding of vector addition in physics
  • Familiarity with trigonometric functions and angles
  • Knowledge of wind vector impact on flight dynamics
  • Basic principles of relative velocity
NEXT STEPS
  • Calculate the resultant vector using vector addition techniques
  • Explore the concept of relative velocity in aviation
  • Study the effects of wind on flight paths using simulation tools
  • Learn about navigation adjustments in aviation under varying wind conditions
USEFUL FOR

Aviation students, pilots, and aerodynamics engineers seeking to optimize flight paths in windy conditions will benefit from this discussion.

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Homework Statement


A pilot needs to fly his plane to a location due east as fast as possible. The plane is capable of flying at a top speed of 140 km/h in still air. In this case the wind is blowing exactly NE at 42.5 km/h. In which direction should the pilot point the plane? What will be the planes speed toward its destination?


Homework Equations





The Attempt at a Solution


Well all I have here is the diagram that I drew on the XY plane, with the plane starting at 0 and a vector going east at 140 km/h...and another vector going from the origin to NE at 45°... so the resultant vector should be the I hats and J hats added...so for the magnitude its the i hat and j hat squared and the square root of that...and the angle is y hat over i hat which would be the 45.

Since I'm looking for what direction the pilot needs to fly in order to end up at the destination...shouldn't the resultant vector be the negative...(well opposite) of the vector I had just figured out? And the angle should be the 45 from 360 since its basically going from quadrent 1 to quadrent 4? Am I heading in the right direction here?
 
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What you want to have is the SUM of the wind's vector and the plane'e vector point straight eastward.
 
The plane can fly at 140 km/h in still air. The velocity of the wind is added to that velocity with respect to air and the resultant points to East. That eastward speed is not 140 km/h. See picture. Find the angle θ.

ehild
 

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