Optimization of a Cylinder's Height and Radius

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To optimize the height and radius of a cylindrical can for maximum volume using a fixed surface area of 6 square centimeters, start with the formulas for volume (V = πr²h) and surface area (SA = 2πrh + 2πr²). Rearrange the surface area equation to express height (h) in terms of radius (r). Substitute this expression for h into the volume formula to create a volume function dependent on a single variable, r. Finally, use calculus to find the maximum volume by determining the critical points of this function. This method effectively combines geometry and optimization techniques to solve the problem.
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A cylindrical can with height h and radius r is to be used to store vegetarian chilli. It
is to be made with 6 square centimetres of tin. Find the height h and radius r which
maximizes the volume of the can.
Hint: The volume of a cylinder is r2h and the surface area of the side walls of a cylinder
is 2rh. The can will also have a top and a bottom, of course — even veggie chilli spoils
if not sealed completely.


I don't know how to solve this question. The mechanics aren't important to me, I'm more concerned of the method. Can somebody explain their methodology for such a question? Thank you!
 
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What are the formulas for volume and surface area? The formula for volume is given. Part of the formula for surface area is given- as the problem says, you need to add the areas of the top and bottom. Both formulas have two variables, the height and radius of the can. Use the information about surface area to solve for one variable and put it into the formula for volume so you have volume depending on one variable.

Do you know how to find max or min of a function of one variable?
(For this particular problem there are two very different methods.)
 
I'm also having trouble with this problem. Given your recommendation, I added the area of the top and bottom to the surface area formula. The top and bottom are just circles so here's what I got:

SA = 2*pi*r*h + 2*pi*r^2

If I solve for h and plug into the volume formula (pi*r^2*h), where do I go from here?
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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