Optimizing f(p,q) with Close Proximity of p and q in (0,1): A Formal Analysis

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Homework Help Overview

The discussion revolves around the function f(p,q) = p(1-p)/[q(1-q)], where p and q are constrained within the interval (0,1). The original poster seeks a formal method to express the relationship between p and q when they are close to each other, particularly in terms of how this proximity affects the value of f(p,q).

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster considers expressing f(p,q) as 1 + ε(p,q) and is looking for a condition "X" that would make ε small. They contemplate substituting q with p + u and exploring Taylor series or L'Hôpital's rule. Other participants suggest defining a related function g(x) = x(1-x) and examining limits as p approaches q.

Discussion Status

The discussion is active with various approaches being explored, including limit definitions and function substitutions. Participants are engaging with the original poster's ideas and offering suggestions without reaching a consensus on a specific method or conclusion.

Contextual Notes

There is a mention of the original poster's uncertainty regarding their calculus skills, which may influence their approach to the problem. The discussion also reflects on the formal definitions of limits and the potential need for epsilon-delta arguments.

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Homework Statement



I have the function f(p,q)=p(1-p)/[q(1-q)] where p and q are in (0,1). I want to say that if p is close to q, f(p,q) is 'close' to 1. What is a formal way of saying how close to p q should be?

The Attempt at a Solution



Basically I want to say [tex]f(p,q)= 1 + \epsilon(p,q)[/tex] where [tex]\epsilon(p,q)[/tex] is small if some condition "X" is true. Is there an obvious way of saying what "X" is? Maybe I can substitute q=p+u... but then what? Taylor series or L'hopital's or something? My calc is pretty rusty, so I'd appreciate any reminders...
 
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Substituting p = q+u sounds like a good idea. Then use
[tex] (q+u)(1-q-u) = q-q^2-2qu+u-u^2 = q(1-q)-2qu+u-u^2[/tex]
 
If you define a function

[tex] g(x) = x (1 - x)[/tex]

can you translate the question you asked in terms of it?
 
Why not just write that the limit[f(p,q)] = 1 as p [tex]\rightarrow[/tex] q ?
 
Raskolnikov said:
Why not just write that the limit[f(p,q)] = 1 as p [tex]\rightarrow[/tex] q ?

I agree.
The problem statement is nearly the very definition of a Limit.
You just did not use the letters epsilon and delta x.
 
[tex]\frac{p(1-p)}{q(1- q)}= \left(\frac{p}{q}\right)\left(\frac{1-p}{1-q}\right)[/tex]
Does that help?
 

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