Optimizing Projectile Distance on an Inclined Plane

  • Thread starter Thread starter leitz
  • Start date Start date
  • Tags Tags
    Plane Projectile
Click For Summary
SUMMARY

The discussion focuses on optimizing projectile distance on an inclined plane, specifically determining the optimal launch angle θ for maximum distance d when thrown from a base at an angle ϕ. Two formulas are presented: 1/2arctan(-cotϕ) = θ and π/4 + ϕ/2. The latter formula is confirmed to yield 45 degrees when φ=0, while the former fails at this angle. The discussion emphasizes the importance of understanding both formulas and encourages further exploration of projectile motion on inclines.

PREREQUISITES
  • Understanding of projectile motion principles
  • Familiarity with trigonometric functions and their applications
  • Basic knowledge of calculus for derivation of formulas
  • Ability to analyze motion on inclined planes
NEXT STEPS
  • Research "Derivation of projectile motion equations" for deeper insights
  • Study "Trigonometric identities in physics" to enhance understanding
  • Explore "Applications of calculus in physics" for advanced problem-solving techniques
  • Investigate "Projectile motion on inclined planes" for practical examples and applications
USEFUL FOR

Students studying physics, educators teaching projectile motion concepts, and anyone interested in optimizing projectile trajectories on inclined surfaces.

leitz
Messages
8
Reaction score
0

Homework Statement


"A person stands at the base of a hill that is a straight incline making an angle ϕ with the horizontal. For a given initial speed v₀, at what angle θ (to the horizontal) should objects be thrown so that the distance d they land up the hill is as large as possible?"

I've looked up the same question on the internet, but the answers are either the formula (1/2arctan(-cotϕ) = θ) or π/4+ ϕ/2. I already figured out how to get 1/2arctan(-cotϕ) = θ, but I do not know how they got they π/4+ ϕ/2. Also, which is the correct answer?

Homework Equations



1/2arctan(-cotϕ) = θ
 
Last edited:
Physics news on Phys.org
The π/4 + φ/2 formula predicts 45 degrees when φ=0, which is certainly correct. The arctan formula doesn't work at φ=0. At φ=45 degrees, the first formula predicts a reasonable 67.5 degrees, while the arctan formula seems to say -22.5 degrees. Better check my calc; I make mistakes.

The second formula is pretty well known. No doubt you could find a derivation of it on the web. Try searching for "Projectile motion on an incline". Of course it is always better to figure it out yourself if you have the time.
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 7 ·
Replies
7
Views
5K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 9 ·
Replies
9
Views
3K
Replies
2
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
40
Views
3K