Optimizing Pulley Sizes for Speed Matching

  • Thread starter Thread starter yoleven
  • Start date Start date
  • Tags Tags
    Pulley Rotation
Click For Summary

Homework Help Overview

The problem involves determining the appropriate diameter of a pulley on a second machine to achieve a desired rotational speed, given the specifications of a first pulley connected by a belt. The subject area relates to rotational motion and pulley systems.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss setting up ratios to relate the speeds and diameters of the pulleys. Some express confusion about the relationship between pulley size and rotational speed, questioning whether a smaller pulley would indeed result in a slower rotation.

Discussion Status

The discussion includes various attempts to establish a relationship between the two pulleys using ratios. Some participants have provided calculations, while others are seeking clarification on the implications of their findings regarding pulley sizes and speeds.

Contextual Notes

There is some uncertainty regarding the assumptions made about the relationship between pulley diameter and rotational speed, as well as the implications of the calculations presented. Participants are navigating through these assumptions without a clear consensus on the correct approach.

yoleven
Messages
78
Reaction score
1

Homework Statement


A tractor has a belt pulley diameter of 10 inch operating at 1100 revolutions per minute. The pulley is connected by a belt to another machine that needs to operate at 650 rpm. What size should the pulley be on the second machine?


Homework Equations


2Pi*r



The Attempt at a Solution


I don't really know where to start. I know that a wheels circumference is 2Pi*r
The first wheel is 10 inches so
2*Pi*5 inches = 1100rpm
if the second wheel has to operate at 650
can I get it by 650/2pi=103 inches?
 
Physics news on Phys.org
Set up a simple ratio.

[tex]\frac {1100} {10} = \frac {650} x[/tex]
 
thank you
 
I'm still a bit unclear. Sorry.
If I set up a ratio
1100/10=650/x
I get an answer of 5.9
I need the second wheel to rotate slower but if it is smaller won't it spin faster?
 
I tried this again.
This seems to work.

driven pulley rpm= drive pulley rpm * drive pulley diameter/driven pulley diameter

650rpm=1100rpm*10inch/x
650x=11000
x=16.923 inch diameter for the pulley
 

Similar threads

  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 6 ·
Replies
6
Views
3K
Replies
16
Views
4K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 19 ·
Replies
19
Views
4K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K