Optimizing Resonance Length for Closed-End Pipe with a Tuning Fork

[Exhausted]

Homework Statement

A tube is closed at one end by a piston which is slowly withdrawn as a tuning fork of frequency 512 Hz is sounded over it. What is the shortest length of pipe which will resonate with the fork?
(Speed of sound is 340m/s)

Homework Equations

L=1/4λ
f=v/(4L)

The Attempt at a Solution

Since the question wants the shortest length for resonance, so set L=1/4λ → 4L=λ
Then, f=v/(4L) → 512=340/(4L) → L=0.16m

Is the answer and the way i approached this question correct?

 

[ehild]

)

The Attempt at a Solution

Since the question wants the shortest length for resonance, so set L=1/4λ → 4L=λ
Then, f=v/(4L) → 512=340/(4L) → L=0.16m

Is the answer and the way i approached this question correct?

It is correct but a little rounding error.

ehild

 

[Exhausted]

Thanks :D