Order of Dark Fringes: Understanding Interference Patterns

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The discussion focuses on understanding the order of dark fringes in interference patterns. The concept of identifying the m=0 dark fringe is highlighted, noting that when a lens is in contact, the center represents the zero ring, which can appear wide. A suggested approach is to derive an equation for the difference between adjacent rings, simplifying the identification of fringe order. It is recommended to measure the diameter of the rings instead of the radius for accuracy, as determining the exact center can be challenging. Accurate measurements and proper graphing techniques are essential for calculating wavelength effectively.
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See attachment please.
After that, please point out, the order of the dark fringes. I mean I can't see where is m=0 dark fringe? Where to start?
I want to know so I can know that radius enclosed by each fringe.
Thanks.
 

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If the lens is in contact then the center is "ring" zero, but it's very wide.

It's been many years but if I remember correctly... You probably have an equation for the radius of the ring, however when doing the experiment it might be best to write an equation for the difference between two adjacent rings. Then you don't need to know which is ring zero or even measure it. Your equation will have a term something like (n+1) -n which equals 1 so the ring number dissapears.

If you plot a graph and it doesn't pass through the origin either you started counting from the wrong place or the lens wasn't really in contact. Either way the slope of the graph wouldn't change and can be used to calculate the wavelength.

I'd also measure the diameter of the rings rather than the radius because it's hard to know where the centre is exactly. The rings have thickness so you have to measure from the middle of the line to mddle of line.
 
I built a device designed to brake angular velocity which seems to work based on below, i used a flexible shaft that could bow up and down so i could visually see what was happening for the prototypes. If you spin two wheels in opposite directions each with a magnitude of angular momentum L on a rigid shaft (equal magnitude opposite directions), then rotate the shaft at 90 degrees to the momentum vectors at constant angular velocity omega, then the resulting torques oppose each other...

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