Ordinary Differential Equation System with Variable Coefficients

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Homework Statement


For [tex]t\in\mathbb{R}[/tex], let:

[tex]A=\left[\begin{array}{ccc}<br /> -1 & 0 & 0\\<br /> 0 & 2 & 2t\\<br /> 0 & 0 & 2\end{array}\right][/tex]

Get the solution for the general equation: [tex]X'=A(t)X[/tex]

Homework Equations



The Attempt at a Solution


I done many of these problems, all with constant coefficients, but I don't know how to do in this case.
 
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Did you know that the solution to
[tex]x'(t) = f(t) x(t)[/tex]
is
[tex]x(t) = x_0 \exp\left( \int_{t_0}^t f(\xi) \, d\xi \right)[/tex]
?
 
Yes, I know. That's the formula I use after getting the exponential matrix, by "diagonalizing" the matrix A. My problem is that I'm not sure if I can do it as I do with constant coefficients, because supposedly it should be different.