Ordinary differential equations

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SUMMARY

The discussion focuses on finding equilibrium solutions for the ordinary differential equation (ODE) initial-value problem defined by z" = z − z^3, with initial conditions z(0) = z0 and z'(0) = v0. The equilibrium solutions identified are 0, 1, and -1. To linearize the problem around these solutions, the process involves representing the ODE as a coupled system of first-order ODEs, applying transformations to shift the equilibrium point to the origin, and computing the Jacobian at the equilibrium point to convert the system into a linear form.

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tasha10
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Find equilibrium solutions for the following ODE initial-value
problem and linearize the problem about those solutions
z" = z − z^3,
z(0) = z0
z'(0) = v0

i found the equilibrium solutions to be 0,1,-1. what are the steps to linearize the problem around these?
 
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I believe you represent it as a coupled system of first-order ODEs, then translate the equilibrium point to the origin via the transformations u=x-x_0 and v=y-y_0. Then compute the Jacobian at the equilibrium point and thus convert the system to a linear system with an equilibrium point at the origin. Try and find "Differential Equations" by Blanchard, Devaney, and Hall. It's an easy read and does a lot of work with systems.
 

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