Ordinary matrix-vector multiplication

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Homework Help Overview

The discussion revolves around the properties of a function defined on the space of column vectors in \(\mathbb{R}^2\) using a real symmetric 2x2 matrix \(P\). Participants are exploring the conditions under which this function can be considered an inner product.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are questioning the meaning of the notation \(Pw\) in the context of the inner product definition. There is confusion regarding whether the function outputs scalars and the dimensionality of the vectors involved.

Discussion Status

The discussion is ongoing, with participants clarifying the nature of the vectors \(v\) and \(w\) as well as the function's domain. Some guidance has been provided regarding the dimensionality of the vectors and the interpretation of the function.

Contextual Notes

There is a focus on the definitions and properties of inner products, particularly in relation to the requirements for the matrix \(P\) and the dimensions of the vectors involved. Participants are also addressing potential misunderstandings about the function's output.

Treadstone 71
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Let [tex]P=(p_{ij})[/tex] be a real symmetric 2x2 matrix. Show that the function on [tex]\mathbb{R}^2\times\mathbb{R}^2[/tex] (Where R^2 is a space of column vectors) defined by [tex]<v,w>=v^tPw[/tex] is an inner product if and only if [tex]p_{11}[/tex] and [tex]det(P)[/tex] are both swtrictly positive.

I just need to know what [tex]Pw[/tex] means in [tex]<v,w>=v^tPw[/tex].
 
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Ordinary matrix-vector multiplication.
 
I see. I thought it was "P of w".
 
This function doesn't send vectors to scalars, it can't be an inner product, unless I understood something wrong.
 
v and w are 1x2 column vectors, right? So why is this function on R^2xR^2? Isn't it defined on the vector space R^2?
 
Treadstone 71 said:
v and w are 1x2 column vectors, right? So why is this function on R^2xR^2? Isn't it defined on the vector space R^2?

they're 2x1, but there are two of them. This function takes a pair of vectors, (v,w) and gives a real number, so the domain is R^2xR^2.
 
v is in R2, w is in R2 so (v, w) is in R2 x R2.
 

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