# Organ Pipe and Fundamental Frequency

1. Aug 3, 2008

### yellowgators

1. The problem statement, all variables and given/known data
The organ pipe is 2.0 m long, was open at both ends, and was originally tuned to a fundamental frequency of 128 Hz (C below middle C).
a) what is the wavelength of the fundamental?
b)if the note you now hear is closer to 262 Hz (middle C), where is the blockage with respect to the opening at the bottom of the pipe?

2. Relevant equations
for a pipe open on both ends: lambda=2L

3. The attempt at a solution
a) lambda=2L= 4.0 m
b) I know the pipe will have a displacement antinode at each end, and a pressure node at each end. I don't understand how to find L given only the frequency 262 Hz; I looked at all my equations, but couldn't find one that seemed to work.
$$v=f\lambda$$
Using that relationship you can change the frequency in wavelength ($$speed\ of\ sound=330 ms^{-1}$$ if not specified.) So from there it's should be pretty straight forward to solve for $$L$$