Organic Chem- Mechanism Question(Oxidation of Glycol)

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SUMMARY

The discussion focuses on the detailed mechanism of glycol oxidation by periodic acid, specifically the formation of cyclic periodate as an intermediate. The oxidation process involves cleavage of the C-C bond in the glycol, resulting in two carbonyl groups. The oxidation state of iodine is preserved in the cyclic periodate, which acts as an electron acceptor. Participants emphasize the importance of understanding the role of hydroxyl groups in the mechanism and the formation of water from periodic acid during the reaction.

PREREQUISITES
  • Understanding of organic reaction mechanisms, particularly oxidation reactions.
  • Familiarity with periodic acid and its role in organic chemistry.
  • Knowledge of nucleophilic substitution reactions (SN reactions).
  • Basic concepts of oxidation states and electron transfer in chemical reactions.
NEXT STEPS
  • Study the mechanism of glycol oxidation by periodic acid in detail.
  • Learn about the formation and stability of cyclic periodate intermediates.
  • Explore nucleophilic substitution reactions involving alcohols and their leaving groups.
  • Investigate the role of solvent interactions in organic reaction mechanisms.
USEFUL FOR

Chemistry students, organic chemists, and anyone studying reaction mechanisms in organic synthesis will benefit from this discussion.

HclGuy
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Homework Statement


Write a detailed mechanism for the following reaction:
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The Attempt at a Solution



Okay, I know this is PART of the mechanism for the oxidation of a glycol by periodic acid which causes cleavage of the C-C bond between the glycol and forms 2 carbonyl groups. The thing is the cyclic periodate that is formed is only an intermediate , and I need to figure out a mechanism for that 1 Step. I have tried thinking about turning one of the -OH groups on the glycol into H2O to start a SN reaction, but it doesn't seem to work out. What I think I do know is that the oxidation state of the iodine atom is preserved in the cyclic periodate and that the periodic acid is the molecule that wants electrons. Other than that, I don't have a clue about how the mechanism works to form the cyclic periodate.
 

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If you were to label the oxygens (O-18) of the glycol, would the intermediate contain both? If so, the H2O produced comes from periodic acid. From there, the mechanism is fairly straightforward... attach things that have electron density to things that don't. Intermediates that are positively charged and contain a proton, likely lose the proton to the solvent. The solvated protons can reprotonate elsewhere on the intermediate.
 
Thanks for the tip !, haven't thought about the oxygens from the glycol being the one on the cyclic periodate, was so obsessed with trying to turn one of the alcohols on the glycol into a leaving group and not the alcohol on the periodic acid.
 

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