Oscillation / Soundwaves Question - Phase difference?

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Homework Help Overview

The problem involves two speakers emitting sound waves in phase, with an observer positioned at different distances from each speaker. The objective is to determine the phase difference between the waves at the observer's location, given the frequency of the sound and the speed of sound in air.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the meaning of phase difference and its relation to distance and wavelength. There are attempts to visualize the problem graphically and relate distances to phase shifts. Questions arise about how to calculate the phase difference in radians based on the distances involved.

Discussion Status

The discussion is ongoing, with participants exploring different aspects of the problem, including the need for the wavelength to calculate the phase difference. Some guidance has been offered regarding the relationship between wave speed, frequency, and wavelength, but no consensus has been reached on a specific approach.

Contextual Notes

Participants note the importance of calculating the wavelength based on the given frequency and speed of sound, as well as the need to clarify assumptions about the phase difference and its calculation.

LadyMario
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An observer stands 3 m from speaker A and 4 m from speaker B. Both speakers,
oscillating in phase, produce 170 Hz waves. The speed of sound in air is 340 m/s.
What is the phase difference (in radians) between the waves from A and B at the
observer’s location, point P?


And I have no idea how to solve this :confused: :rolleyes:

Basically looks like:

P---------B (4m away)
|
|
|
|
A (3m away)
 
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Think about what what a phase difference means, and then think about wavelengths and distances, and how all three are related.
 
tms said:
Think about what what a phase difference means, and then think about wavelengths and distances, and how all three are related.

I get that graphically a phase shift means it's literally shifted across the x-axis. But I can't think of an equation that would relate this an the distance.
 
If you draw two sine waves, one shifted a bit relative to the other, on the same graph, a distance should jump out at you.
 
tms said:
If you draw two sine waves, one shifted a bit relative to the other, on the same graph, a distance should jump out at you.

:confused: But we don't know the phase...

I get that they're 1m apart and it covers 340 m every second so the phase would be out of sync by 1/340.. do I convert that to radians then?
 
The 340 m/sec is the speed of sound. You need to know the wavelength of the emitted sound, and compare that to the distance between the speakers.
 
tms said:
The 340 m/sec is the speed of sound. You need to know the wavelength of the emitted sound, and compare that to the distance between the speakers.

Okay, so it travels 170 waves / s and one of the speakers is 1m further so it's out of phase by 170 waves (not sure how to get that into rads) but I feel like we need the speed of sound in there somewhere..
 
LadyMario said:
Okay, so it travels 170 waves / s and one of the speakers is 1m further so it's out of phase by 170 waves
You are assuming that the wavelength is one meter; that is something you need to calculate using the wave speed and the frequency.
 

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