Oscillation Spring Dampening Find Frequency

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SUMMARY

The discussion centers on calculating the frequency of an oscillating spring dampening system using the formula w = sqrt(ect). The user initially calculated b/2m as 0.287129 and the square root component as 1.128713, leading to an incorrect frequency of 0.255. The correct frequency, however, is 0.180, highlighting the importance of ignoring the imaginary portion in the calculations.

PREREQUISITES
  • Understanding of oscillation mechanics
  • Familiarity with spring dampening systems
  • Knowledge of the formula w = sqrt(ect)
  • Basic grasp of frequency calculations involving 2π
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  • Research the derivation of the formula w = sqrt(ect)
  • Learn about the role of damping in oscillatory systems
  • Explore methods for calculating frequency in spring systems
  • Study the implications of imaginary numbers in physical equations
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JoeyBob
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Homework Statement
See attached
Relevant Equations
w=ib/2m+sqrt(k/m-(b/2m)^2)
So first I found what b/2m is and got 0.287129. Then I found what the sqrt part of the equation was and got 1.128713. Then I added them together to find w. Then I divided by 2pi to find frequency and got 0.255, but the answer is 0.180.
 

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nvm w=sqrt(ect). You ignore the imaginary portion for whatever reason.
 

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