Oval Track Motion: Velocity Vectors G and H

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An object moving clockwise on an oval track experiences decreasing speed, with velocity vectors G and H positioned closely together. If point H is moved closer to G, the velocity vector's magnitude decreases, while its direction may change based on the track's curvature. The acceleration at point G can be calculated using the formula a = (vf - vi)/t, where vf is the final velocity, vi is the initial velocity, and t is the time interval. The direction of acceleration aligns with the change in the velocity vector, influenced by the object's speed and the track's curvature. Understanding these dynamics is essential for analyzing motion on curved paths.
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An object moves clockwise with decreasing speed around an oval track. THe velocity vectors are in the top right side of the oval labeled G and H respectively. They lie fairly close to one another. I have a few questions:

IF point H were chosen to lie closer to point G, describe how the change in velocity vector would change (direction and magnitude)?
I am thinking that the direction would stay the same but the magnitude would decrease because the time intervals are smaller.

Describe how you determine the acceleration at point G (direction and mag)?
I have no idea!
 
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If point H were chosen to lie closer to point G, the change in velocity vector would indeed result in a decrease in magnitude. However, the direction may also change depending on the curvature of the oval track. If the track has a sharper turn near point G, the direction of the velocity vector at point H may change to align with the curvature of the track. This is because the object is experiencing a change in direction as it moves around the track.

To determine the acceleration at point G, we can use the formula a = (vf - vi)/t, where vf is the final velocity, vi is the initial velocity, and t is the time interval. In this case, we can use the velocity vectors G and H to calculate the change in velocity and divide it by the time interval between the two points. The direction of the acceleration would be in the same direction as the change in velocity vector, and the magnitude would depend on the speed at which the object is traveling and the curvature of the track at that point.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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