Overshooting in a critically damped oscillator

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    Damped Oscillator
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SUMMARY

The discussion focuses on determining the conditions under which a critically damped oscillator will overshoot its equilibrium position based on the initial velocity (v0). It is established that a sufficiently high v0 guarantees overshooting, while a low v0 results in behavior akin to starting from a farther point without overshooting. The response to a step function remains consistent in shape, merely scaled by the input magnitude. Clarity is sought on the implications of these conditions for predicting oscillator behavior.

PREREQUISITES
  • Understanding of critically damped oscillators
  • Familiarity with initial velocity (v0) concepts
  • Knowledge of step function responses in control systems
  • Basic principles of oscillatory motion and equilibrium
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Arijun
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How can we tell whether a given v0 will cause an oscillator to overshoot the equilibrium? If the velocity high enough, we know the oscillator will overshoot and return to equilibrium. But if v0 is low, the system would act like it came from a point a bit farther out and not overshoot (right?). So how would we figure out which it will be?
 
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The response to a step of function of any magnitude will be the same shape but scaled to the size of the input step.
 
I don't understand your response at all. Could you clarify?
 

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